/[dtapublic]/projs/trunk/shared_source/c_tk_base_7_5_w_mods/tktrig.c
ViewVC logotype

Contents of /projs/trunk/shared_source/c_tk_base_7_5_w_mods/tktrig.c

Parent Directory Parent Directory | Revision Log Revision Log


Revision 71 - (show annotations) (download)
Sat Nov 5 11:07:06 2016 UTC (8 years ago) by dashley
File MIME type: text/plain
File size: 41021 byte(s)
Set EOL properties appropriately to facilitate simultaneous Linux and Windows development.
1 /* $Header$ */
2
3 /*
4 * tkTrig.c --
5 *
6 * This file contains a collection of trigonometry utility
7 * routines that are used by Tk and in particular by the
8 * canvas code. It also has miscellaneous geometry functions
9 * used by canvases.
10 *
11 * Copyright (c) 1992-1994 The Regents of the University of California.
12 * Copyright (c) 1994-1997 Sun Microsystems, Inc.
13 *
14 * See the file "license.terms" for information on usage and redistribution
15 * of this file, and for a DISCLAIMER OF ALL WARRANTIES.
16 *
17 * RCS: @(#) $Id: tktrig.c,v 1.1.1.1 2001/06/13 05:11:18 dtashley Exp $
18 */
19
20 #include <stdio.h>
21 #include "tkInt.h"
22 #include "tkPort.h"
23 #include "tkCanvas.h"
24
25 #undef MIN
26 #define MIN(a,b) (((a) < (b)) ? (a) : (b))
27 #undef MAX
28 #define MAX(a,b) (((a) > (b)) ? (a) : (b))
29 #ifndef PI
30 # define PI 3.14159265358979323846
31 #endif /* PI */
32
33 /*
34 *--------------------------------------------------------------
35 *
36 * TkLineToPoint --
37 *
38 * Compute the distance from a point to a finite line segment.
39 *
40 * Results:
41 * The return value is the distance from the line segment
42 * whose end-points are *end1Ptr and *end2Ptr to the point
43 * given by *pointPtr.
44 *
45 * Side effects:
46 * None.
47 *
48 *--------------------------------------------------------------
49 */
50
51 double
52 TkLineToPoint(end1Ptr, end2Ptr, pointPtr)
53 double end1Ptr[2]; /* Coordinates of first end-point of line. */
54 double end2Ptr[2]; /* Coordinates of second end-point of line. */
55 double pointPtr[2]; /* Points to coords for point. */
56 {
57 double x, y;
58
59 /*
60 * Compute the point on the line that is closest to the
61 * point. This must be done separately for vertical edges,
62 * horizontal edges, and other edges.
63 */
64
65 if (end1Ptr[0] == end2Ptr[0]) {
66
67 /*
68 * Vertical edge.
69 */
70
71 x = end1Ptr[0];
72 if (end1Ptr[1] >= end2Ptr[1]) {
73 y = MIN(end1Ptr[1], pointPtr[1]);
74 y = MAX(y, end2Ptr[1]);
75 } else {
76 y = MIN(end2Ptr[1], pointPtr[1]);
77 y = MAX(y, end1Ptr[1]);
78 }
79 } else if (end1Ptr[1] == end2Ptr[1]) {
80
81 /*
82 * Horizontal edge.
83 */
84
85 y = end1Ptr[1];
86 if (end1Ptr[0] >= end2Ptr[0]) {
87 x = MIN(end1Ptr[0], pointPtr[0]);
88 x = MAX(x, end2Ptr[0]);
89 } else {
90 x = MIN(end2Ptr[0], pointPtr[0]);
91 x = MAX(x, end1Ptr[0]);
92 }
93 } else {
94 double m1, b1, m2, b2;
95
96 /*
97 * The edge is neither horizontal nor vertical. Convert the
98 * edge to a line equation of the form y = m1*x + b1. Then
99 * compute a line perpendicular to this edge but passing
100 * through the point, also in the form y = m2*x + b2.
101 */
102
103 m1 = (end2Ptr[1] - end1Ptr[1])/(end2Ptr[0] - end1Ptr[0]);
104 b1 = end1Ptr[1] - m1*end1Ptr[0];
105 m2 = -1.0/m1;
106 b2 = pointPtr[1] - m2*pointPtr[0];
107 x = (b2 - b1)/(m1 - m2);
108 y = m1*x + b1;
109 if (end1Ptr[0] > end2Ptr[0]) {
110 if (x > end1Ptr[0]) {
111 x = end1Ptr[0];
112 y = end1Ptr[1];
113 } else if (x < end2Ptr[0]) {
114 x = end2Ptr[0];
115 y = end2Ptr[1];
116 }
117 } else {
118 if (x > end2Ptr[0]) {
119 x = end2Ptr[0];
120 y = end2Ptr[1];
121 } else if (x < end1Ptr[0]) {
122 x = end1Ptr[0];
123 y = end1Ptr[1];
124 }
125 }
126 }
127
128 /*
129 * Compute the distance to the closest point.
130 */
131
132 return hypot(pointPtr[0] - x, pointPtr[1] - y);
133 }
134
135 /*
136 *--------------------------------------------------------------
137 *
138 * TkLineToArea --
139 *
140 * Determine whether a line lies entirely inside, entirely
141 * outside, or overlapping a given rectangular area.
142 *
143 * Results:
144 * -1 is returned if the line given by end1Ptr and end2Ptr
145 * is entirely outside the rectangle given by rectPtr. 0 is
146 * returned if the polygon overlaps the rectangle, and 1 is
147 * returned if the polygon is entirely inside the rectangle.
148 *
149 * Side effects:
150 * None.
151 *
152 *--------------------------------------------------------------
153 */
154
155 int
156 TkLineToArea(end1Ptr, end2Ptr, rectPtr)
157 double end1Ptr[2]; /* X and y coordinates for one endpoint
158 * of line. */
159 double end2Ptr[2]; /* X and y coordinates for other endpoint
160 * of line. */
161 double rectPtr[4]; /* Points to coords for rectangle, in the
162 * order x1, y1, x2, y2. X1 must be no
163 * larger than x2, and y1 no larger than y2. */
164 {
165 int inside1, inside2;
166
167 /*
168 * First check the two points individually to see whether they
169 * are inside the rectangle or not.
170 */
171
172 inside1 = (end1Ptr[0] >= rectPtr[0]) && (end1Ptr[0] <= rectPtr[2])
173 && (end1Ptr[1] >= rectPtr[1]) && (end1Ptr[1] <= rectPtr[3]);
174 inside2 = (end2Ptr[0] >= rectPtr[0]) && (end2Ptr[0] <= rectPtr[2])
175 && (end2Ptr[1] >= rectPtr[1]) && (end2Ptr[1] <= rectPtr[3]);
176 if (inside1 != inside2) {
177 return 0;
178 }
179 if (inside1 & inside2) {
180 return 1;
181 }
182
183 /*
184 * Both points are outside the rectangle, but still need to check
185 * for intersections between the line and the rectangle. Horizontal
186 * and vertical lines are particularly easy, so handle them
187 * separately.
188 */
189
190 if (end1Ptr[0] == end2Ptr[0]) {
191 /*
192 * Vertical line.
193 */
194
195 if (((end1Ptr[1] >= rectPtr[1]) ^ (end2Ptr[1] >= rectPtr[1]))
196 && (end1Ptr[0] >= rectPtr[0])
197 && (end1Ptr[0] <= rectPtr[2])) {
198 return 0;
199 }
200 } else if (end1Ptr[1] == end2Ptr[1]) {
201 /*
202 * Horizontal line.
203 */
204
205 if (((end1Ptr[0] >= rectPtr[0]) ^ (end2Ptr[0] >= rectPtr[0]))
206 && (end1Ptr[1] >= rectPtr[1])
207 && (end1Ptr[1] <= rectPtr[3])) {
208 return 0;
209 }
210 } else {
211 double m, x, y, low, high;
212
213 /*
214 * Diagonal line. Compute slope of line and use
215 * for intersection checks against each of the
216 * sides of the rectangle: left, right, bottom, top.
217 */
218
219 m = (end2Ptr[1] - end1Ptr[1])/(end2Ptr[0] - end1Ptr[0]);
220 if (end1Ptr[0] < end2Ptr[0]) {
221 low = end1Ptr[0]; high = end2Ptr[0];
222 } else {
223 low = end2Ptr[0]; high = end1Ptr[0];
224 }
225
226 /*
227 * Left edge.
228 */
229
230 y = end1Ptr[1] + (rectPtr[0] - end1Ptr[0])*m;
231 if ((rectPtr[0] >= low) && (rectPtr[0] <= high)
232 && (y >= rectPtr[1]) && (y <= rectPtr[3])) {
233 return 0;
234 }
235
236 /*
237 * Right edge.
238 */
239
240 y += (rectPtr[2] - rectPtr[0])*m;
241 if ((y >= rectPtr[1]) && (y <= rectPtr[3])
242 && (rectPtr[2] >= low) && (rectPtr[2] <= high)) {
243 return 0;
244 }
245
246 /*
247 * Bottom edge.
248 */
249
250 if (end1Ptr[1] < end2Ptr[1]) {
251 low = end1Ptr[1]; high = end2Ptr[1];
252 } else {
253 low = end2Ptr[1]; high = end1Ptr[1];
254 }
255 x = end1Ptr[0] + (rectPtr[1] - end1Ptr[1])/m;
256 if ((x >= rectPtr[0]) && (x <= rectPtr[2])
257 && (rectPtr[1] >= low) && (rectPtr[1] <= high)) {
258 return 0;
259 }
260
261 /*
262 * Top edge.
263 */
264
265 x += (rectPtr[3] - rectPtr[1])/m;
266 if ((x >= rectPtr[0]) && (x <= rectPtr[2])
267 && (rectPtr[3] >= low) && (rectPtr[3] <= high)) {
268 return 0;
269 }
270 }
271 return -1;
272 }
273
274 /*
275 *--------------------------------------------------------------
276 *
277 * TkThickPolyLineToArea --
278 *
279 * This procedure is called to determine whether a connected
280 * series of line segments lies entirely inside, entirely
281 * outside, or overlapping a given rectangular area.
282 *
283 * Results:
284 * -1 is returned if the lines are entirely outside the area,
285 * 0 if they overlap, and 1 if they are entirely inside the
286 * given area.
287 *
288 * Side effects:
289 * None.
290 *
291 *--------------------------------------------------------------
292 */
293
294 /* ARGSUSED */
295 int
296 TkThickPolyLineToArea(coordPtr, numPoints, width, capStyle, joinStyle, rectPtr)
297 double *coordPtr; /* Points to an array of coordinates for
298 * the polyline: x0, y0, x1, y1, ... */
299 int numPoints; /* Total number of points at *coordPtr. */
300 double width; /* Width of each line segment. */
301 int capStyle; /* How are end-points of polyline drawn?
302 * CapRound, CapButt, or CapProjecting. */
303 int joinStyle; /* How are joints in polyline drawn?
304 * JoinMiter, JoinRound, or JoinBevel. */
305 double *rectPtr; /* Rectangular area to check against. */
306 {
307 double radius, poly[10];
308 int count;
309 int changedMiterToBevel; /* Non-zero means that a mitered corner
310 * had to be treated as beveled after all
311 * because the angle was < 11 degrees. */
312 int inside; /* Tentative guess about what to return,
313 * based on all points seen so far: one
314 * means everything seen so far was
315 * inside the area; -1 means everything
316 * was outside the area. 0 means overlap
317 * has been found. */
318
319 radius = width/2.0;
320 inside = -1;
321
322 if ((coordPtr[0] >= rectPtr[0]) && (coordPtr[0] <= rectPtr[2])
323 && (coordPtr[1] >= rectPtr[1]) && (coordPtr[1] <= rectPtr[3])) {
324 inside = 1;
325 }
326
327 /*
328 * Iterate through all of the edges of the line, computing a polygon
329 * for each edge and testing the area against that polygon. In
330 * addition, there are additional tests to deal with rounded joints
331 * and caps.
332 */
333
334 changedMiterToBevel = 0;
335 for (count = numPoints; count >= 2; count--, coordPtr += 2) {
336
337 /*
338 * If rounding is done around the first point of the edge
339 * then test a circular region around the point with the
340 * area.
341 */
342
343 if (((capStyle == CapRound) && (count == numPoints))
344 || ((joinStyle == JoinRound) && (count != numPoints))) {
345 poly[0] = coordPtr[0] - radius;
346 poly[1] = coordPtr[1] - radius;
347 poly[2] = coordPtr[0] + radius;
348 poly[3] = coordPtr[1] + radius;
349 if (TkOvalToArea(poly, rectPtr) != inside) {
350 return 0;
351 }
352 }
353
354 /*
355 * Compute the polygonal shape corresponding to this edge,
356 * consisting of two points for the first point of the edge
357 * and two points for the last point of the edge.
358 */
359
360 if (count == numPoints) {
361 TkGetButtPoints(coordPtr+2, coordPtr, width,
362 capStyle == CapProjecting, poly, poly+2);
363 } else if ((joinStyle == JoinMiter) && !changedMiterToBevel) {
364 poly[0] = poly[6];
365 poly[1] = poly[7];
366 poly[2] = poly[4];
367 poly[3] = poly[5];
368 } else {
369 TkGetButtPoints(coordPtr+2, coordPtr, width, 0, poly, poly+2);
370
371 /*
372 * If the last joint was beveled, then also check a
373 * polygon comprising the last two points of the previous
374 * polygon and the first two from this polygon; this checks
375 * the wedges that fill the beveled joint.
376 */
377
378 if ((joinStyle == JoinBevel) || changedMiterToBevel) {
379 poly[8] = poly[0];
380 poly[9] = poly[1];
381 if (TkPolygonToArea(poly, 5, rectPtr) != inside) {
382 return 0;
383 }
384 changedMiterToBevel = 0;
385 }
386 }
387 if (count == 2) {
388 TkGetButtPoints(coordPtr, coordPtr+2, width,
389 capStyle == CapProjecting, poly+4, poly+6);
390 } else if (joinStyle == JoinMiter) {
391 if (TkGetMiterPoints(coordPtr, coordPtr+2, coordPtr+4,
392 (double) width, poly+4, poly+6) == 0) {
393 changedMiterToBevel = 1;
394 TkGetButtPoints(coordPtr, coordPtr+2, width, 0, poly+4,
395 poly+6);
396 }
397 } else {
398 TkGetButtPoints(coordPtr, coordPtr+2, width, 0, poly+4, poly+6);
399 }
400 poly[8] = poly[0];
401 poly[9] = poly[1];
402 if (TkPolygonToArea(poly, 5, rectPtr) != inside) {
403 return 0;
404 }
405 }
406
407 /*
408 * If caps are rounded, check the cap around the final point
409 * of the line.
410 */
411
412 if (capStyle == CapRound) {
413 poly[0] = coordPtr[0] - radius;
414 poly[1] = coordPtr[1] - radius;
415 poly[2] = coordPtr[0] + radius;
416 poly[3] = coordPtr[1] + radius;
417 if (TkOvalToArea(poly, rectPtr) != inside) {
418 return 0;
419 }
420 }
421
422 return inside;
423 }
424
425 /*
426 *--------------------------------------------------------------
427 *
428 * TkPolygonToPoint --
429 *
430 * Compute the distance from a point to a polygon.
431 *
432 * Results:
433 * The return value is 0.0 if the point referred to by
434 * pointPtr is within the polygon referred to by polyPtr
435 * and numPoints. Otherwise the return value is the
436 * distance of the point from the polygon.
437 *
438 * Side effects:
439 * None.
440 *
441 *--------------------------------------------------------------
442 */
443
444 double
445 TkPolygonToPoint(polyPtr, numPoints, pointPtr)
446 double *polyPtr; /* Points to an array coordinates for
447 * closed polygon: x0, y0, x1, y1, ...
448 * The polygon may be self-intersecting. */
449 int numPoints; /* Total number of points at *polyPtr. */
450 double *pointPtr; /* Points to coords for point. */
451 {
452 double bestDist; /* Closest distance between point and
453 * any edge in polygon. */
454 int intersections; /* Number of edges in the polygon that
455 * intersect a ray extending vertically
456 * upwards from the point to infinity. */
457 int count;
458 register double *pPtr;
459
460 /*
461 * Iterate through all of the edges in the polygon, updating
462 * bestDist and intersections.
463 *
464 * TRICKY POINT: when computing intersections, include left
465 * x-coordinate of line within its range, but not y-coordinate.
466 * Otherwise if the point lies exactly below a vertex we'll
467 * count it as two intersections.
468 */
469
470 bestDist = 1.0e36;
471 intersections = 0;
472
473 for (count = numPoints, pPtr = polyPtr; count > 1; count--, pPtr += 2) {
474 double x, y, dist;
475
476 /*
477 * Compute the point on the current edge closest to the point
478 * and update the intersection count. This must be done
479 * separately for vertical edges, horizontal edges, and
480 * other edges.
481 */
482
483 if (pPtr[2] == pPtr[0]) {
484
485 /*
486 * Vertical edge.
487 */
488
489 x = pPtr[0];
490 if (pPtr[1] >= pPtr[3]) {
491 y = MIN(pPtr[1], pointPtr[1]);
492 y = MAX(y, pPtr[3]);
493 } else {
494 y = MIN(pPtr[3], pointPtr[1]);
495 y = MAX(y, pPtr[1]);
496 }
497 } else if (pPtr[3] == pPtr[1]) {
498
499 /*
500 * Horizontal edge.
501 */
502
503 y = pPtr[1];
504 if (pPtr[0] >= pPtr[2]) {
505 x = MIN(pPtr[0], pointPtr[0]);
506 x = MAX(x, pPtr[2]);
507 if ((pointPtr[1] < y) && (pointPtr[0] < pPtr[0])
508 && (pointPtr[0] >= pPtr[2])) {
509 intersections++;
510 }
511 } else {
512 x = MIN(pPtr[2], pointPtr[0]);
513 x = MAX(x, pPtr[0]);
514 if ((pointPtr[1] < y) && (pointPtr[0] < pPtr[2])
515 && (pointPtr[0] >= pPtr[0])) {
516 intersections++;
517 }
518 }
519 } else {
520 double m1, b1, m2, b2;
521 int lower; /* Non-zero means point below line. */
522
523 /*
524 * The edge is neither horizontal nor vertical. Convert the
525 * edge to a line equation of the form y = m1*x + b1. Then
526 * compute a line perpendicular to this edge but passing
527 * through the point, also in the form y = m2*x + b2.
528 */
529
530 m1 = (pPtr[3] - pPtr[1])/(pPtr[2] - pPtr[0]);
531 b1 = pPtr[1] - m1*pPtr[0];
532 m2 = -1.0/m1;
533 b2 = pointPtr[1] - m2*pointPtr[0];
534 x = (b2 - b1)/(m1 - m2);
535 y = m1*x + b1;
536 if (pPtr[0] > pPtr[2]) {
537 if (x > pPtr[0]) {
538 x = pPtr[0];
539 y = pPtr[1];
540 } else if (x < pPtr[2]) {
541 x = pPtr[2];
542 y = pPtr[3];
543 }
544 } else {
545 if (x > pPtr[2]) {
546 x = pPtr[2];
547 y = pPtr[3];
548 } else if (x < pPtr[0]) {
549 x = pPtr[0];
550 y = pPtr[1];
551 }
552 }
553 lower = (m1*pointPtr[0] + b1) > pointPtr[1];
554 if (lower && (pointPtr[0] >= MIN(pPtr[0], pPtr[2]))
555 && (pointPtr[0] < MAX(pPtr[0], pPtr[2]))) {
556 intersections++;
557 }
558 }
559
560 /*
561 * Compute the distance to the closest point, and see if that
562 * is the best distance seen so far.
563 */
564
565 dist = hypot(pointPtr[0] - x, pointPtr[1] - y);
566 if (dist < bestDist) {
567 bestDist = dist;
568 }
569 }
570
571 /*
572 * We've processed all of the points. If the number of intersections
573 * is odd, the point is inside the polygon.
574 */
575
576 if (intersections & 0x1) {
577 return 0.0;
578 }
579 return bestDist;
580 }
581
582 /*
583 *--------------------------------------------------------------
584 *
585 * TkPolygonToArea --
586 *
587 * Determine whether a polygon lies entirely inside, entirely
588 * outside, or overlapping a given rectangular area.
589 *
590 * Results:
591 * -1 is returned if the polygon given by polyPtr and numPoints
592 * is entirely outside the rectangle given by rectPtr. 0 is
593 * returned if the polygon overlaps the rectangle, and 1 is
594 * returned if the polygon is entirely inside the rectangle.
595 *
596 * Side effects:
597 * None.
598 *
599 *--------------------------------------------------------------
600 */
601
602 int
603 TkPolygonToArea(polyPtr, numPoints, rectPtr)
604 double *polyPtr; /* Points to an array coordinates for
605 * closed polygon: x0, y0, x1, y1, ...
606 * The polygon may be self-intersecting. */
607 int numPoints; /* Total number of points at *polyPtr. */
608 register double *rectPtr; /* Points to coords for rectangle, in the
609 * order x1, y1, x2, y2. X1 and y1 must
610 * be lower-left corner. */
611 {
612 int state; /* State of all edges seen so far (-1 means
613 * outside, 1 means inside, won't ever be
614 * 0). */
615 int count;
616 register double *pPtr;
617
618 /*
619 * Iterate over all of the edges of the polygon and test them
620 * against the rectangle. Can quit as soon as the state becomes
621 * "intersecting".
622 */
623
624 state = TkLineToArea(polyPtr, polyPtr+2, rectPtr);
625 if (state == 0) {
626 return 0;
627 }
628 for (pPtr = polyPtr+2, count = numPoints-1; count >= 2;
629 pPtr += 2, count--) {
630 if (TkLineToArea(pPtr, pPtr+2, rectPtr) != state) {
631 return 0;
632 }
633 }
634
635 /*
636 * If all of the edges were inside the rectangle we're done.
637 * If all of the edges were outside, then the rectangle could
638 * still intersect the polygon (if it's entirely enclosed).
639 * Call TkPolygonToPoint to figure this out.
640 */
641
642 if (state == 1) {
643 return 1;
644 }
645 if (TkPolygonToPoint(polyPtr, numPoints, rectPtr) == 0.0) {
646 return 0;
647 }
648 return -1;
649 }
650
651 /*
652 *--------------------------------------------------------------
653 *
654 * TkOvalToPoint --
655 *
656 * Computes the distance from a given point to a given
657 * oval, in canvas units.
658 *
659 * Results:
660 * The return value is 0 if the point given by *pointPtr is
661 * inside the oval. If the point isn't inside the
662 * oval then the return value is approximately the distance
663 * from the point to the oval. If the oval is filled, then
664 * anywhere in the interior is considered "inside"; if
665 * the oval isn't filled, then "inside" means only the area
666 * occupied by the outline.
667 *
668 * Side effects:
669 * None.
670 *
671 *--------------------------------------------------------------
672 */
673
674 /* ARGSUSED */
675 double
676 TkOvalToPoint(ovalPtr, width, filled, pointPtr)
677 double ovalPtr[4]; /* Pointer to array of four coordinates
678 * (x1, y1, x2, y2) defining oval's bounding
679 * box. */
680 double width; /* Width of outline for oval. */
681 int filled; /* Non-zero means oval should be treated as
682 * filled; zero means only consider outline. */
683 double pointPtr[2]; /* Coordinates of point. */
684 {
685 double xDelta, yDelta, scaledDistance, distToOutline, distToCenter;
686 double xDiam, yDiam;
687
688 /*
689 * Compute the distance between the center of the oval and the
690 * point in question, using a coordinate system where the oval
691 * has been transformed to a circle with unit radius.
692 */
693
694 xDelta = (pointPtr[0] - (ovalPtr[0] + ovalPtr[2])/2.0);
695 yDelta = (pointPtr[1] - (ovalPtr[1] + ovalPtr[3])/2.0);
696 distToCenter = hypot(xDelta, yDelta);
697 scaledDistance = hypot(xDelta / ((ovalPtr[2] + width - ovalPtr[0])/2.0),
698 yDelta / ((ovalPtr[3] + width - ovalPtr[1])/2.0));
699
700
701 /*
702 * If the scaled distance is greater than 1 then it means no
703 * hit. Compute the distance from the point to the edge of
704 * the circle, then scale this distance back to the original
705 * coordinate system.
706 *
707 * Note: this distance isn't completely accurate. It's only
708 * an approximation, and it can overestimate the correct
709 * distance when the oval is eccentric.
710 */
711
712 if (scaledDistance > 1.0) {
713 return (distToCenter/scaledDistance) * (scaledDistance - 1.0);
714 }
715
716 /*
717 * Scaled distance less than 1 means the point is inside the
718 * outer edge of the oval. If this is a filled oval, then we
719 * have a hit. Otherwise, do the same computation as above
720 * (scale back to original coordinate system), but also check
721 * to see if the point is within the width of the outline.
722 */
723
724 if (filled) {
725 return 0.0;
726 }
727 if (scaledDistance > 1E-10) {
728 distToOutline = (distToCenter/scaledDistance) * (1.0 - scaledDistance)
729 - width;
730 } else {
731 /*
732 * Avoid dividing by a very small number (it could cause an
733 * arithmetic overflow). This problem occurs if the point is
734 * very close to the center of the oval.
735 */
736
737 xDiam = ovalPtr[2] - ovalPtr[0];
738 yDiam = ovalPtr[3] - ovalPtr[1];
739 if (xDiam < yDiam) {
740 distToOutline = (xDiam - width)/2;
741 } else {
742 distToOutline = (yDiam - width)/2;
743 }
744 }
745
746 if (distToOutline < 0.0) {
747 return 0.0;
748 }
749 return distToOutline;
750 }
751
752 /*
753 *--------------------------------------------------------------
754 *
755 * TkOvalToArea --
756 *
757 * Determine whether an oval lies entirely inside, entirely
758 * outside, or overlapping a given rectangular area.
759 *
760 * Results:
761 * -1 is returned if the oval described by ovalPtr is entirely
762 * outside the rectangle given by rectPtr. 0 is returned if the
763 * oval overlaps the rectangle, and 1 is returned if the oval
764 * is entirely inside the rectangle.
765 *
766 * Side effects:
767 * None.
768 *
769 *--------------------------------------------------------------
770 */
771
772 int
773 TkOvalToArea(ovalPtr, rectPtr)
774 register double *ovalPtr; /* Points to coordinates definining the
775 * bounding rectangle for the oval: x1, y1,
776 * x2, y2. X1 must be less than x2 and y1
777 * less than y2. */
778 register double *rectPtr; /* Points to coords for rectangle, in the
779 * order x1, y1, x2, y2. X1 and y1 must
780 * be lower-left corner. */
781 {
782 double centerX, centerY, radX, radY, deltaX, deltaY;
783
784 /*
785 * First, see if oval is entirely inside rectangle or entirely
786 * outside rectangle.
787 */
788
789 if ((rectPtr[0] <= ovalPtr[0]) && (rectPtr[2] >= ovalPtr[2])
790 && (rectPtr[1] <= ovalPtr[1]) && (rectPtr[3] >= ovalPtr[3])) {
791 return 1;
792 }
793 if ((rectPtr[2] < ovalPtr[0]) || (rectPtr[0] > ovalPtr[2])
794 || (rectPtr[3] < ovalPtr[1]) || (rectPtr[1] > ovalPtr[3])) {
795 return -1;
796 }
797
798 /*
799 * Next, go through the rectangle side by side. For each side
800 * of the rectangle, find the point on the side that is closest
801 * to the oval's center, and see if that point is inside the
802 * oval. If at least one such point is inside the oval, then
803 * the rectangle intersects the oval.
804 */
805
806 centerX = (ovalPtr[0] + ovalPtr[2])/2;
807 centerY = (ovalPtr[1] + ovalPtr[3])/2;
808 radX = (ovalPtr[2] - ovalPtr[0])/2;
809 radY = (ovalPtr[3] - ovalPtr[1])/2;
810
811 deltaY = rectPtr[1] - centerY;
812 if (deltaY < 0.0) {
813 deltaY = centerY - rectPtr[3];
814 if (deltaY < 0.0) {
815 deltaY = 0;
816 }
817 }
818 deltaY /= radY;
819 deltaY *= deltaY;
820
821 /*
822 * Left side:
823 */
824
825 deltaX = (rectPtr[0] - centerX)/radX;
826 deltaX *= deltaX;
827 if ((deltaX + deltaY) <= 1.0) {
828 return 0;
829 }
830
831 /*
832 * Right side:
833 */
834
835 deltaX = (rectPtr[2] - centerX)/radX;
836 deltaX *= deltaX;
837 if ((deltaX + deltaY) <= 1.0) {
838 return 0;
839 }
840
841 deltaX = rectPtr[0] - centerX;
842 if (deltaX < 0.0) {
843 deltaX = centerX - rectPtr[2];
844 if (deltaX < 0.0) {
845 deltaX = 0;
846 }
847 }
848 deltaX /= radX;
849 deltaX *= deltaX;
850
851 /*
852 * Bottom side:
853 */
854
855 deltaY = (rectPtr[1] - centerY)/radY;
856 deltaY *= deltaY;
857 if ((deltaX + deltaY) < 1.0) {
858 return 0;
859 }
860
861 /*
862 * Top side:
863 */
864
865 deltaY = (rectPtr[3] - centerY)/radY;
866 deltaY *= deltaY;
867 if ((deltaX + deltaY) < 1.0) {
868 return 0;
869 }
870
871 return -1;
872 }
873
874 /*
875 *--------------------------------------------------------------
876 *
877 * TkIncludePoint --
878 *
879 * Given a point and a generic canvas item header, expand
880 * the item's bounding box if needed to include the point.
881 *
882 * Results:
883 * None.
884 *
885 * Side effects:
886 * The boudn.
887 *
888 *--------------------------------------------------------------
889 */
890
891 /* ARGSUSED */
892 void
893 TkIncludePoint(itemPtr, pointPtr)
894 register Tk_Item *itemPtr; /* Item whose bounding box is
895 * being calculated. */
896 double *pointPtr; /* Address of two doubles giving
897 * x and y coordinates of point. */
898 {
899 int tmp;
900
901 tmp = (int) (pointPtr[0] + 0.5);
902 if (tmp < itemPtr->x1) {
903 itemPtr->x1 = tmp;
904 }
905 if (tmp > itemPtr->x2) {
906 itemPtr->x2 = tmp;
907 }
908 tmp = (int) (pointPtr[1] + 0.5);
909 if (tmp < itemPtr->y1) {
910 itemPtr->y1 = tmp;
911 }
912 if (tmp > itemPtr->y2) {
913 itemPtr->y2 = tmp;
914 }
915 }
916
917 /*
918 *--------------------------------------------------------------
919 *
920 * TkBezierScreenPoints --
921 *
922 * Given four control points, create a larger set of XPoints
923 * for a Bezier spline based on the points.
924 *
925 * Results:
926 * The array at *xPointPtr gets filled in with numSteps XPoints
927 * corresponding to the Bezier spline defined by the four
928 * control points. Note: no output point is generated for the
929 * first input point, but an output point *is* generated for
930 * the last input point.
931 *
932 * Side effects:
933 * None.
934 *
935 *--------------------------------------------------------------
936 */
937
938 void
939 TkBezierScreenPoints(canvas, control, numSteps, xPointPtr)
940 Tk_Canvas canvas; /* Canvas in which curve is to be
941 * drawn. */
942 double control[]; /* Array of coordinates for four
943 * control points: x0, y0, x1, y1,
944 * ... x3 y3. */
945 int numSteps; /* Number of curve points to
946 * generate. */
947 register XPoint *xPointPtr; /* Where to put new points. */
948 {
949 int i;
950 double u, u2, u3, t, t2, t3;
951
952 for (i = 1; i <= numSteps; i++, xPointPtr++) {
953 t = ((double) i)/((double) numSteps);
954 t2 = t*t;
955 t3 = t2*t;
956 u = 1.0 - t;
957 u2 = u*u;
958 u3 = u2*u;
959 Tk_CanvasDrawableCoords(canvas,
960 (control[0]*u3 + 3.0 * (control[2]*t*u2 + control[4]*t2*u)
961 + control[6]*t3),
962 (control[1]*u3 + 3.0 * (control[3]*t*u2 + control[5]*t2*u)
963 + control[7]*t3),
964 &xPointPtr->x, &xPointPtr->y);
965 }
966 }
967
968 /*
969 *--------------------------------------------------------------
970 *
971 * TkBezierPoints --
972 *
973 * Given four control points, create a larger set of points
974 * for a Bezier spline based on the points.
975 *
976 * Results:
977 * The array at *coordPtr gets filled in with 2*numSteps
978 * coordinates, which correspond to the Bezier spline defined
979 * by the four control points. Note: no output point is
980 * generated for the first input point, but an output point
981 * *is* generated for the last input point.
982 *
983 * Side effects:
984 * None.
985 *
986 *--------------------------------------------------------------
987 */
988
989 void
990 TkBezierPoints(control, numSteps, coordPtr)
991 double control[]; /* Array of coordinates for four
992 * control points: x0, y0, x1, y1,
993 * ... x3 y3. */
994 int numSteps; /* Number of curve points to
995 * generate. */
996 register double *coordPtr; /* Where to put new points. */
997 {
998 int i;
999 double u, u2, u3, t, t2, t3;
1000
1001 for (i = 1; i <= numSteps; i++, coordPtr += 2) {
1002 t = ((double) i)/((double) numSteps);
1003 t2 = t*t;
1004 t3 = t2*t;
1005 u = 1.0 - t;
1006 u2 = u*u;
1007 u3 = u2*u;
1008 coordPtr[0] = control[0]*u3
1009 + 3.0 * (control[2]*t*u2 + control[4]*t2*u) + control[6]*t3;
1010 coordPtr[1] = control[1]*u3
1011 + 3.0 * (control[3]*t*u2 + control[5]*t2*u) + control[7]*t3;
1012 }
1013 }
1014
1015 /*
1016 *--------------------------------------------------------------
1017 *
1018 * TkMakeBezierCurve --
1019 *
1020 * Given a set of points, create a new set of points that fit
1021 * parabolic splines to the line segments connecting the original
1022 * points. Produces output points in either of two forms.
1023 *
1024 * Note: in spite of this procedure's name, it does *not* generate
1025 * Bezier curves. Since only three control points are used for
1026 * each curve segment, not four, the curves are actually just
1027 * parabolic.
1028 *
1029 * Results:
1030 * Either or both of the xPoints or dblPoints arrays are filled
1031 * in. The return value is the number of points placed in the
1032 * arrays. Note: if the first and last points are the same, then
1033 * a closed curve is generated.
1034 *
1035 * Side effects:
1036 * None.
1037 *
1038 *--------------------------------------------------------------
1039 */
1040
1041 int
1042 TkMakeBezierCurve(canvas, pointPtr, numPoints, numSteps, xPoints, dblPoints)
1043 Tk_Canvas canvas; /* Canvas in which curve is to be
1044 * drawn. */
1045 double *pointPtr; /* Array of input coordinates: x0,
1046 * y0, x1, y1, etc.. */
1047 int numPoints; /* Number of points at pointPtr. */
1048 int numSteps; /* Number of steps to use for each
1049 * spline segments (determines
1050 * smoothness of curve). */
1051 XPoint xPoints[]; /* Array of XPoints to fill in (e.g.
1052 * for display. NULL means don't
1053 * fill in any XPoints. */
1054 double dblPoints[]; /* Array of points to fill in as
1055 * doubles, in the form x0, y0,
1056 * x1, y1, .... NULL means don't
1057 * fill in anything in this form.
1058 * Caller must make sure that this
1059 * array has enough space. */
1060 {
1061 int closed, outputPoints, i;
1062 int numCoords = numPoints*2;
1063 double control[8];
1064
1065 /*
1066 * If the curve is a closed one then generate a special spline
1067 * that spans the last points and the first ones. Otherwise
1068 * just put the first point into the output.
1069 */
1070
1071 if (!pointPtr) {
1072 /* Of pointPtr == NULL, this function returns an upper limit.
1073 * of the array size to store the coordinates. This can be
1074 * used to allocate storage, before the actual coordinates
1075 * are calculated. */
1076 return 1 + numPoints * numSteps;
1077 }
1078
1079 outputPoints = 0;
1080 if ((pointPtr[0] == pointPtr[numCoords-2])
1081 && (pointPtr[1] == pointPtr[numCoords-1])) {
1082 closed = 1;
1083 control[0] = 0.5*pointPtr[numCoords-4] + 0.5*pointPtr[0];
1084 control[1] = 0.5*pointPtr[numCoords-3] + 0.5*pointPtr[1];
1085 control[2] = 0.167*pointPtr[numCoords-4] + 0.833*pointPtr[0];
1086 control[3] = 0.167*pointPtr[numCoords-3] + 0.833*pointPtr[1];
1087 control[4] = 0.833*pointPtr[0] + 0.167*pointPtr[2];
1088 control[5] = 0.833*pointPtr[1] + 0.167*pointPtr[3];
1089 control[6] = 0.5*pointPtr[0] + 0.5*pointPtr[2];
1090 control[7] = 0.5*pointPtr[1] + 0.5*pointPtr[3];
1091 if (xPoints != NULL) {
1092 Tk_CanvasDrawableCoords(canvas, control[0], control[1],
1093 &xPoints->x, &xPoints->y);
1094 TkBezierScreenPoints(canvas, control, numSteps, xPoints+1);
1095 xPoints += numSteps+1;
1096 }
1097 if (dblPoints != NULL) {
1098 dblPoints[0] = control[0];
1099 dblPoints[1] = control[1];
1100 TkBezierPoints(control, numSteps, dblPoints+2);
1101 dblPoints += 2*(numSteps+1);
1102 }
1103 outputPoints += numSteps+1;
1104 } else {
1105 closed = 0;
1106 if (xPoints != NULL) {
1107 Tk_CanvasDrawableCoords(canvas, pointPtr[0], pointPtr[1],
1108 &xPoints->x, &xPoints->y);
1109 xPoints += 1;
1110 }
1111 if (dblPoints != NULL) {
1112 dblPoints[0] = pointPtr[0];
1113 dblPoints[1] = pointPtr[1];
1114 dblPoints += 2;
1115 }
1116 outputPoints += 1;
1117 }
1118
1119 for (i = 2; i < numPoints; i++, pointPtr += 2) {
1120 /*
1121 * Set up the first two control points. This is done
1122 * differently for the first spline of an open curve
1123 * than for other cases.
1124 */
1125
1126 if ((i == 2) && !closed) {
1127 control[0] = pointPtr[0];
1128 control[1] = pointPtr[1];
1129 control[2] = 0.333*pointPtr[0] + 0.667*pointPtr[2];
1130 control[3] = 0.333*pointPtr[1] + 0.667*pointPtr[3];
1131 } else {
1132 control[0] = 0.5*pointPtr[0] + 0.5*pointPtr[2];
1133 control[1] = 0.5*pointPtr[1] + 0.5*pointPtr[3];
1134 control[2] = 0.167*pointPtr[0] + 0.833*pointPtr[2];
1135 control[3] = 0.167*pointPtr[1] + 0.833*pointPtr[3];
1136 }
1137
1138 /*
1139 * Set up the last two control points. This is done
1140 * differently for the last spline of an open curve
1141 * than for other cases.
1142 */
1143
1144 if ((i == (numPoints-1)) && !closed) {
1145 control[4] = .667*pointPtr[2] + .333*pointPtr[4];
1146 control[5] = .667*pointPtr[3] + .333*pointPtr[5];
1147 control[6] = pointPtr[4];
1148 control[7] = pointPtr[5];
1149 } else {
1150 control[4] = .833*pointPtr[2] + .167*pointPtr[4];
1151 control[5] = .833*pointPtr[3] + .167*pointPtr[5];
1152 control[6] = 0.5*pointPtr[2] + 0.5*pointPtr[4];
1153 control[7] = 0.5*pointPtr[3] + 0.5*pointPtr[5];
1154 }
1155
1156 /*
1157 * If the first two points coincide, or if the last
1158 * two points coincide, then generate a single
1159 * straight-line segment by outputting the last control
1160 * point.
1161 */
1162
1163 if (((pointPtr[0] == pointPtr[2]) && (pointPtr[1] == pointPtr[3]))
1164 || ((pointPtr[2] == pointPtr[4])
1165 && (pointPtr[3] == pointPtr[5]))) {
1166 if (xPoints != NULL) {
1167 Tk_CanvasDrawableCoords(canvas, control[6], control[7],
1168 &xPoints[0].x, &xPoints[0].y);
1169 xPoints++;
1170 }
1171 if (dblPoints != NULL) {
1172 dblPoints[0] = control[6];
1173 dblPoints[1] = control[7];
1174 dblPoints += 2;
1175 }
1176 outputPoints += 1;
1177 continue;
1178 }
1179
1180 /*
1181 * Generate a Bezier spline using the control points.
1182 */
1183
1184
1185 if (xPoints != NULL) {
1186 TkBezierScreenPoints(canvas, control, numSteps, xPoints);
1187 xPoints += numSteps;
1188 }
1189 if (dblPoints != NULL) {
1190 TkBezierPoints(control, numSteps, dblPoints);
1191 dblPoints += 2*numSteps;
1192 }
1193 outputPoints += numSteps;
1194 }
1195 return outputPoints;
1196 }
1197
1198 /*
1199 *--------------------------------------------------------------
1200 *
1201 * TkMakeBezierPostscript --
1202 *
1203 * This procedure generates Postscript commands that create
1204 * a path corresponding to a given Bezier curve.
1205 *
1206 * Results:
1207 * None. Postscript commands to generate the path are appended
1208 * to the interp's result.
1209 *
1210 * Side effects:
1211 * None.
1212 *
1213 *--------------------------------------------------------------
1214 */
1215
1216 void
1217 TkMakeBezierPostscript(interp, canvas, pointPtr, numPoints)
1218 Tcl_Interp *interp; /* Interpreter in whose result the
1219 * Postscript is to be stored. */
1220 Tk_Canvas canvas; /* Canvas widget for which the
1221 * Postscript is being generated. */
1222 double *pointPtr; /* Array of input coordinates: x0,
1223 * y0, x1, y1, etc.. */
1224 int numPoints; /* Number of points at pointPtr. */
1225 {
1226 int closed, i;
1227 int numCoords = numPoints*2;
1228 double control[8];
1229 char buffer[200];
1230
1231 /*
1232 * If the curve is a closed one then generate a special spline
1233 * that spans the last points and the first ones. Otherwise
1234 * just put the first point into the path.
1235 */
1236
1237 if ((pointPtr[0] == pointPtr[numCoords-2])
1238 && (pointPtr[1] == pointPtr[numCoords-1])) {
1239 closed = 1;
1240 control[0] = 0.5*pointPtr[numCoords-4] + 0.5*pointPtr[0];
1241 control[1] = 0.5*pointPtr[numCoords-3] + 0.5*pointPtr[1];
1242 control[2] = 0.167*pointPtr[numCoords-4] + 0.833*pointPtr[0];
1243 control[3] = 0.167*pointPtr[numCoords-3] + 0.833*pointPtr[1];
1244 control[4] = 0.833*pointPtr[0] + 0.167*pointPtr[2];
1245 control[5] = 0.833*pointPtr[1] + 0.167*pointPtr[3];
1246 control[6] = 0.5*pointPtr[0] + 0.5*pointPtr[2];
1247 control[7] = 0.5*pointPtr[1] + 0.5*pointPtr[3];
1248 sprintf(buffer, "%.15g %.15g moveto\n%.15g %.15g %.15g %.15g %.15g %.15g curveto\n",
1249 control[0], Tk_CanvasPsY(canvas, control[1]),
1250 control[2], Tk_CanvasPsY(canvas, control[3]),
1251 control[4], Tk_CanvasPsY(canvas, control[5]),
1252 control[6], Tk_CanvasPsY(canvas, control[7]));
1253 } else {
1254 closed = 0;
1255 control[6] = pointPtr[0];
1256 control[7] = pointPtr[1];
1257 sprintf(buffer, "%.15g %.15g moveto\n",
1258 control[6], Tk_CanvasPsY(canvas, control[7]));
1259 }
1260 Tcl_AppendResult(interp, buffer, (char *) NULL);
1261
1262 /*
1263 * Cycle through all the remaining points in the curve, generating
1264 * a curve section for each vertex in the linear path.
1265 */
1266
1267 for (i = numPoints-2, pointPtr += 2; i > 0; i--, pointPtr += 2) {
1268 control[2] = 0.333*control[6] + 0.667*pointPtr[0];
1269 control[3] = 0.333*control[7] + 0.667*pointPtr[1];
1270
1271 /*
1272 * Set up the last two control points. This is done
1273 * differently for the last spline of an open curve
1274 * than for other cases.
1275 */
1276
1277 if ((i == 1) && !closed) {
1278 control[6] = pointPtr[2];
1279 control[7] = pointPtr[3];
1280 } else {
1281 control[6] = 0.5*pointPtr[0] + 0.5*pointPtr[2];
1282 control[7] = 0.5*pointPtr[1] + 0.5*pointPtr[3];
1283 }
1284 control[4] = 0.333*control[6] + 0.667*pointPtr[0];
1285 control[5] = 0.333*control[7] + 0.667*pointPtr[1];
1286
1287 sprintf(buffer, "%.15g %.15g %.15g %.15g %.15g %.15g curveto\n",
1288 control[2], Tk_CanvasPsY(canvas, control[3]),
1289 control[4], Tk_CanvasPsY(canvas, control[5]),
1290 control[6], Tk_CanvasPsY(canvas, control[7]));
1291 Tcl_AppendResult(interp, buffer, (char *) NULL);
1292 }
1293 }
1294
1295 /*
1296 *--------------------------------------------------------------
1297 *
1298 * TkGetMiterPoints --
1299 *
1300 * Given three points forming an angle, compute the
1301 * coordinates of the inside and outside points of
1302 * the mitered corner formed by a line of a given
1303 * width at that angle.
1304 *
1305 * Results:
1306 * If the angle formed by the three points is less than
1307 * 11 degrees then 0 is returned and m1 and m2 aren't
1308 * modified. Otherwise 1 is returned and the points at
1309 * m1 and m2 are filled in with the positions of the points
1310 * of the mitered corner.
1311 *
1312 * Side effects:
1313 * None.
1314 *
1315 *--------------------------------------------------------------
1316 */
1317
1318 int
1319 TkGetMiterPoints(p1, p2, p3, width, m1, m2)
1320 double p1[]; /* Points to x- and y-coordinates of point
1321 * before vertex. */
1322 double p2[]; /* Points to x- and y-coordinates of vertex
1323 * for mitered joint. */
1324 double p3[]; /* Points to x- and y-coordinates of point
1325 * after vertex. */
1326 double width; /* Width of line. */
1327 double m1[]; /* Points to place to put "left" vertex
1328 * point (see as you face from p1 to p2). */
1329 double m2[]; /* Points to place to put "right" vertex
1330 * point. */
1331 {
1332 double theta1; /* Angle of segment p2-p1. */
1333 double theta2; /* Angle of segment p2-p3. */
1334 double theta; /* Angle between line segments (angle
1335 * of joint). */
1336 double theta3; /* Angle that bisects theta1 and
1337 * theta2 and points to m1. */
1338 double dist; /* Distance of miter points from p2. */
1339 double deltaX, deltaY; /* X and y offsets cooresponding to
1340 * dist (fudge factors for bounding
1341 * box). */
1342 double p1x, p1y, p2x, p2y, p3x, p3y;
1343 static double elevenDegrees = (11.0*2.0*PI)/360.0;
1344
1345 /*
1346 * Round the coordinates to integers to mimic what happens when the
1347 * line segments are displayed; without this code, the bounding box
1348 * of a mitered line can be miscomputed greatly.
1349 */
1350
1351 p1x = floor(p1[0]+0.5);
1352 p1y = floor(p1[1]+0.5);
1353 p2x = floor(p2[0]+0.5);
1354 p2y = floor(p2[1]+0.5);
1355 p3x = floor(p3[0]+0.5);
1356 p3y = floor(p3[1]+0.5);
1357
1358 if (p2y == p1y) {
1359 theta1 = (p2x < p1x) ? 0 : PI;
1360 } else if (p2x == p1x) {
1361 theta1 = (p2y < p1y) ? PI/2.0 : -PI/2.0;
1362 } else {
1363 theta1 = atan2(p1y - p2y, p1x - p2x);
1364 }
1365 if (p3y == p2y) {
1366 theta2 = (p3x > p2x) ? 0 : PI;
1367 } else if (p3x == p2x) {
1368 theta2 = (p3y > p2y) ? PI/2.0 : -PI/2.0;
1369 } else {
1370 theta2 = atan2(p3y - p2y, p3x - p2x);
1371 }
1372 theta = theta1 - theta2;
1373 if (theta > PI) {
1374 theta -= 2*PI;
1375 } else if (theta < -PI) {
1376 theta += 2*PI;
1377 }
1378 if ((theta < elevenDegrees) && (theta > -elevenDegrees)) {
1379 return 0;
1380 }
1381 dist = 0.5*width/sin(0.5*theta);
1382 if (dist < 0.0) {
1383 dist = -dist;
1384 }
1385
1386 /*
1387 * Compute theta3 (make sure that it points to the left when
1388 * looking from p1 to p2).
1389 */
1390
1391 theta3 = (theta1 + theta2)/2.0;
1392 if (sin(theta3 - (theta1 + PI)) < 0.0) {
1393 theta3 += PI;
1394 }
1395 deltaX = dist*cos(theta3);
1396 m1[0] = p2x + deltaX;
1397 m2[0] = p2x - deltaX;
1398 deltaY = dist*sin(theta3);
1399 m1[1] = p2y + deltaY;
1400 m2[1] = p2y - deltaY;
1401 return 1;
1402 }
1403
1404 /*
1405 *--------------------------------------------------------------
1406 *
1407 * TkGetButtPoints --
1408 *
1409 * Given two points forming a line segment, compute the
1410 * coordinates of two endpoints of a rectangle formed by
1411 * bloating the line segment until it is width units wide.
1412 *
1413 * Results:
1414 * There is no return value. M1 and m2 are filled in to
1415 * correspond to m1 and m2 in the diagram below:
1416 *
1417 * ----------------* m1
1418 * |
1419 * p1 *---------------* p2
1420 * |
1421 * ----------------* m2
1422 *
1423 * M1 and m2 will be W units apart, with p2 centered between
1424 * them and m1-m2 perpendicular to p1-p2. However, if
1425 * "project" is true then m1 and m2 will be as follows:
1426 *
1427 * -------------------* m1
1428 * p2 |
1429 * p1 *---------------* |
1430 * |
1431 * -------------------* m2
1432 *
1433 * In this case p2 will be width/2 units from the segment m1-m2.
1434 *
1435 * Side effects:
1436 * None.
1437 *
1438 *--------------------------------------------------------------
1439 */
1440
1441 void
1442 TkGetButtPoints(p1, p2, width, project, m1, m2)
1443 double p1[]; /* Points to x- and y-coordinates of point
1444 * before vertex. */
1445 double p2[]; /* Points to x- and y-coordinates of vertex
1446 * for mitered joint. */
1447 double width; /* Width of line. */
1448 int project; /* Non-zero means project p2 by an additional
1449 * width/2 before computing m1 and m2. */
1450 double m1[]; /* Points to place to put "left" result
1451 * point, as you face from p1 to p2. */
1452 double m2[]; /* Points to place to put "right" result
1453 * point. */
1454 {
1455 double length; /* Length of p1-p2 segment. */
1456 double deltaX, deltaY; /* Increments in coords. */
1457
1458 width *= 0.5;
1459 length = hypot(p2[0] - p1[0], p2[1] - p1[1]);
1460 if (length == 0.0) {
1461 m1[0] = m2[0] = p2[0];
1462 m1[1] = m2[1] = p2[1];
1463 } else {
1464 deltaX = -width * (p2[1] - p1[1]) / length;
1465 deltaY = width * (p2[0] - p1[0]) / length;
1466 m1[0] = p2[0] + deltaX;
1467 m2[0] = p2[0] - deltaX;
1468 m1[1] = p2[1] + deltaY;
1469 m2[1] = p2[1] - deltaY;
1470 if (project) {
1471 m1[0] += deltaY;
1472 m2[0] += deltaY;
1473 m1[1] -= deltaX;
1474 m2[1] -= deltaX;
1475 }
1476 }
1477 }
1478
1479 /* End of tktrig.c */

Properties

Name Value
svn:eol-style native
svn:keywords Header

dashley@gmail.com
ViewVC Help
Powered by ViewVC 1.1.25