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%$Header: /home/dashley/cvsrep/e3ft_gpl01/e3ft_gpl01/dtaipubs/esrgubka/c_mtn0/c_mtn0.tex,v 1.4 2002/12/01 21:29:08 dtashley Exp $
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\chapter[\cmtnzeroshorttitle{}]{\cmtnzerolongtitle{}}
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\label{cmtn0}
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\beginchapterquote{``If intellectual curiosity, professional pride, and ambition are
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the dominant incentives to research, then assuredly no one has
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a fairer chance of gratifying them than a mathematician. His
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subject is the most curious of all---there is none in which
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truth plays such odd pranks. It has the most elaborate
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and the most fascinating technique, and gives unrivaled
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openings for the display of sheer professional skill. Finally,
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as history proves abundantly, mathematical achievement, whatever
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its intrinsic worth, is the most enduring
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of all.''}
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{G.H. Hardy \cite{bibref:b:mathematiciansapology:1940}}
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\section{Introduction}
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%Section Tag: INT0
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\label{cmtn0:sint0}
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\index{floor function@floor function ($\lfloor\cdot\rfloor$)}%
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\index{--@$\lfloor\cdot\rfloor$ (\emph{floor($\cdot$)} function)}%
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\index{ceiling function@ceiling function ($\lceil\cdot\rceil$)}%
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\index{--@$\lceil\cdot\rceil$ (\emph{ceiling($\cdot$)} function)}%
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\section{The Floor \mbox{\boldmath $\lfloor\cdot\rfloor$} And Ceiling \mbox{\boldmath $\lceil\cdot\rceil$} Functions}
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\label{cmtn0:sfcf0}
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The \emph{floor} function, denoted $\lfloor\cdot\rfloor$, is defined to return
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the largest integer not larger than the argument. For example,
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$\lfloor 3 \rfloor = \lfloor 3.9999 \rfloor = 3$. For negative arguments, the definition
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is identical: $\lfloor -4 \rfloor = \lfloor -3.9 \rfloor = -4$.
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The \emph{ceiling} function, denoted $\lceil\cdot\rceil$, is defined to return
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the smallest integer not less than the argument. For example,
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$\lceil 3.0001 \rceil = \lceil 4 \rceil = 4$. For negative arguments, the definition
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is identical: $\lceil -4 \rceil = \lceil -4.9 \rceil = -4$.
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Note that the definitions presented above for negative arguments
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differ from what is commonly implemented in spreadsheet software and other consumer
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software.
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It can be verfied easily that for
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$a \in \vworkintsetnonneg$, $b \in \vworkintsetpos$,
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\begin{equation}
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\label{eq:cmtn0:sfcf0:01}
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\frac{a}{b} = \left\lfloor\frac{a}{b}\right\rfloor + \frac{a \bmod b}{b}
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\end{equation}
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\noindent{}and consequently that
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\begin{equation}
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\label{eq:cmtn0:sfcf0:02}
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\left\lfloor\frac{a}{b}\right\rfloor = \frac{a}{b} - \frac{a \bmod b}{b} .
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\end{equation}
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\noindent{}(\ref{eq:cmtn0:sfcf0:02}) is a very useful identity for
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decomposing expressions involving the \emph{floor($\cdot$)} function.
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\section{Tests For Divisibility Of Integers}
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%Section Tag: TDI0
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\subsection{Tests For Divisibility By 2, 3, 5, 6, 7, And 11}
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It is often useful to be able to inspect a radix-10 integer and quickly
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determine if it can be divided by a small prime number. This section
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presents tests which can be used to easily determine divisibility by
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2, 3, 5, 7, and 11.
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Placeholder\index{divisibility tests for integers!by 0002@by 2}
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reserved for divisibility by 2.
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Placeholder\index{divisibility tests for integers!by 0003@by 3}
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reserved for divisibility by 3.
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Placeholder\index{divisibility tests for integers!by 0005@by 5}
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reserved for divisibility by 5.
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Placeholder\index{divisibility tests for integers!by 0007@by 7}
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reserved for divisibility by 7.
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Placeholder\index{divisibility tests for integers!by 0011@by 11}
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reserved for divisibility by 11.
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\subsection{Tests For Divisibility By 2$^N$, 6, 9, And 10$^N$}
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Placeholder\index{divisibility tests for integers!by 0002N@by 2$^N$}
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reserved for divisibility by 2$^N$.
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Placeholder\index{divisibility tests for integers!by 0006@by 6}
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reserved for divisibility by 6.
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Placeholder\index{divisibility tests for integers!by 0009@by 9}
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reserved for divisibility by 9.
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Placeholder\index{divisibility tests for integers!by 0010N@by 10$^N$}
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reserved for divisibility by 10$^N$.
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\subsection{David G. Radcliffe's Proof: Rearrangement Of Digits Of $2^N$}
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%Subsection Tag: DGR0
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In 07/00, Paul Harvey (\texttt{pharvey@derwent.co.uk}) made the following
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post to \texttt{sci.math} \cite{bibref:n:scimathnewsgroup}:
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\begin{quote}
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{I've got a little problem which is bugging me, perhaps someone out there
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can point me in the right direction \ldots{}}
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{Does there exist a positive integer which is a power of 2, whose digits can
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be rearranged to give a different power of 2?}
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\end{quote}
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David G. Radcliffe \cite{bibref:i:davidgradcliffe}
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responded with a beautiful proof, which is presented below
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as a theorem.
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\begin{vworktheoremstatement}
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No radix-10 positive integral power of 2 (i.e. 1, 2, 4, 8, 16, 32, etc.), with
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any leading 0's removed, can be used
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to form another radix-10 positive integral power of 2 by simple rearrangement
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of the digits.
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\end{vworktheoremstatement}
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\begin{vworktheoremproof}
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Suppose that $x$ and $y$ are two different powers of 2, $y>x$, and that
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the digits of $x$ can be rearranged to form $y$. $y<10x$, since both
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$x$ and $y$ must have the same number of digits. Thus, there
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are three possibilities, $y=2x$, $y=4x$, or $y=8x$.
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Since $x$ and $y$ have the same digits, but in a different order,
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the sum of the digits of $x$ is equal to the sum of the digits of $y$.
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It follows that $y-x$ is divisible by 9. (This follows because
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the sum of the digits of an integer $i$, summing the intermediate
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sums as many times as necessary to yield a single-digit result,
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yield either 9 implying that $i \; mod \; 9 = 0$, or yielding $i \; mod \; 9$.
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If the digits of $x$ and $y$ are the same,
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the sums of their digits are the same, thus $(x \; mod \; 9) = (y \; mod \; 9)$,
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which implies that $((y-x) \; mod \; 9) = 0$, i.e. that $y-x$ is divisible
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by 9.)
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If $y \in \{ 2x, 4x, 8x \}$, then $y-x \in \{ x, 3x, 7x \}$. It would
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follow that $x$ is divisible by 3, a contradiction.
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\end{vworktheoremproof}
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\vworktheoremfooter{}
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\section{The Pigeonhole Principle}
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\label{cmtn0:sphp0}
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The \index{pigeonhole principle}\emph{pigeonhole principle} is a statement
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that if $m$ items are placed into $n$ slots, with $m > n$, then at least one
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slot will contain more than one item. This is also known as
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\index{Dirichlet's box principle}\emph{Dirichlet's box principle}.
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A related statement is that $m$ items are placed into $n$ slots,
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with $m < n$, then at least one
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slot will be empty.
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Despite its simplicity, the pigeonhole principle is the basis for many important
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proofs and observations in number theory.
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\section{Exercises}
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\noindent\begin{figure}[!b]
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\noindent\rule[-0.25in]{\textwidth}{1pt}
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\begin{tiny}
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\begin{verbatim}
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$RCSfile: c_mtn0.tex,v $
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$Source: /home/dashley/cvsrep/e3ft_gpl01/e3ft_gpl01/dtaipubs/esrgubka/c_mtn0/c_mtn0.tex,v $
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$Revision: 1.4 $
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$Author: dtashley $
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$Date: 2002/12/01 21:29:08 $
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\end{verbatim}
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\end{tiny}
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\noindent\rule[0.25in]{\textwidth}{1pt}
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\end{figure}
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% $Log: c_mtn0.tex,v $
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% Revision 1.4 2002/12/01 21:29:08 dtashley
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% Safety checkin.
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%
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% Revision 1.3 2002/07/31 04:37:50 dtashley
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% Number theory chapter title changed, some material added.
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%
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% Revision 1.2 2001/07/01 19:43:13 dtashley
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% Move out of binary mode for use with CVS.
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%
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% $History: c_mtn0.tex $
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%
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% ***************** Version 3 *****************
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% User: Dashley1 Date: 12/22/00 Time: 12:56a
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% Updated in $/uC Software Multi-Volume Book (A)/Chapter, MTN0, Miscellaneous Topics From Number Theory
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% Tcl automated method of build refined.
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%
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% ***************** Version 2 *****************
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% User: David T. Ashley Date: 7/29/00 Time: 11:49p
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% Updated in $/uC Software Multi-Volume Book (A)/Chapter, MTN0, Miscellaneous Topics From Number Theory
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% Edits, addition of solutions manual volume.
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%
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% ***************** Version 1 *****************
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% User: David T. Ashley Date: 7/29/00 Time: 9:34p
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% Created in $/uC Software Multi-Volume Book (A)/Chapter, MTN0, Miscellaneous Topics From Number Theory
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% Initial check-in.
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%
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%End of file C_MTN0.TEX
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